Now i tried it out, and ya, it doesn't work really well.
The vorschlag button simply counts through teh text, and then shows a suggestet decrypt-value.
Method: normally the "e" has the greatest numbers in a text. So, if the "d" is most greatest, the text was crypted with 1.
So u should try decryption with 1. (so if u don't wanna remember ur code, simply enter at the end of the text some eeeeeeeeeeeeeeeeeeeeee's.
Hey, and just remember - it isn't my program - mine will follow
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